select * from flickr.photos.search where text="itajubá"

My first try to get license information was showing the pertinent part of JSON output. You could see that there isn’t a field telling that, but if you look at documentation there’s a “license” parameter.

“farm”: “5″,
“id”: “4458853758″,
“isfamily”: “0″,
“isfriend”: “0″,
“ispublic”: “1″,
“owner”: “76062736@N00″,
“secret”: “9edcd7aea8″,
“server”: “4003″,
“title”: “Clube”

Flickr! has seven options to licensing your photo (again I didn’t found in documentation, I tried each one)

• None (All rights reserved) [ license="0" ]
• Attribution-NonCommercial-ShareAlike Creative Commons [ license="1" ]
• Attribution-NonCommercial Creative Commons [ license="2" ]
• Attribution-NonCommercial-NoDerivs Creative Commons [ license="3" ]
• Attribution Creative Commons [ license="4" ]
• Attribution-ShareAlike Creative Commons [ license="5" ]
• Attribution-NoDerivs Creative Commons [ license="6" ]

My friend was looking to a way to download all photos from Yahoo! Open Hack Brazil so I decided to create a quick way to get theses photos (respecting copyrighted material). My query looks like:

select * from flickr.photos.search(0,2000) where tags="brhackday" and license="1,2,3,4,5,6"

After tests I put the URL from YQL virtual console in my Python code (that parses JSON) and generate a Shell Script to download (using curl/wget)

import simplejson
import urllib 
 
f = open("download.sh","w+")
f.write("#!/bin/sh\n")
i = 0
while True:
 
	url_base="http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20flickr.photos.search(" + str(i) 
+ "%2C" + str(i+100) +")%20where%20tags%3D%22brhackday%22%20and%20license%3D%221%2C2%2C3%2C4%2C5%2C6%22
&format=json" 	
 
	rest = simplejson.load(urllib.urlopen(url_base))['query']
 
        if rest['count'] == '0':
		f.close()
		exit() 
 
	photos = rest['results']['photo'] 
 
	for photo in photos:
		id = photo['id']
		owner = photo['owner']
		d = "curl -s http://www.flickr.com/photos/%s/%s/sizes/o 
| egrep \"<p><img src=\" 
| sed 's/<p>//g ; s/<br \/>//g ; s/<\/p>//g ; s/<img src=\"//g ; s/\" \/>//g' 
| xargs wget ;" % (owner, id)
		f.write(d+'\n')
		i += 100
 
f.close()

Probably If you cut & paste the code they will not work due some indentation issue, so I published in gist here.

The usage I simple:

$ python flickr-d.py
$ sh download.sh

This was a extremely simple workaround but I expect you enjoy!

1. Criar uma chave na API do Flickr!
2. Download do binding para acesso a API (flickrapi)

Nas distribuições Linux, um dos jeitos de instalar é usar o easy_install

easy_install flickrapi

Um modo eficaz para fazer o upload das fotos no serviço seria um script que varre e submete todas as imagens, por exemplo, de uma pasta definida. O exemplo abaixo recebe como parâmetro um diretório e busca por todos os arquivos com extensão .jpg. A função status é apenas para mostrar o andamento do upload e é executada como uma chamada callback no método flickr.upload(). Nos meus testes, precisei pegar o número definido na variável token, antes, executando na interface de linha de comando do Python os seguintes passos:

>>> api_key = "<API>"
>>> secret = "<CHAVE SECRETA>"
>>> username = "<USER>"
>>> flickr = flickrapi.FlickrAPI(api_key,secret,username)
>>> (token, frob) = flickr.get_token_part_one(perms="write")
>>> print token
>>> print frob

Na hora o browser padrão irá abrir e pedir para você confirmar o uso do aplicativo.

# -*- coding: utf-8 -*-
#/bin/python 
 
import sys
import glob 
import flickrapi
 
api_key = "<API>"
secret = "<CHAVE SECRETA>"
username = "<USER>"
 
token="<TOKEN>"
frob=None
 
def status(progress, done):
	if done:
		print "Finished ;-)"
	else:
		print "At %s%%" % progress
 
def upload(photo):
	flickr.upload(photo, callback=status)
 
if __name__ == "__main__":
 
        flickr = flickrapi.FlickrAPI(api_key,secret,username)
        flickr.get_token_part_two((token,frob))
 
        photos = sys.argv[1]+"*.jpg"
 
	for photo in glob.glob(photos):
		print "Uploading: ",photo
		upload(photo)

Um exemplo de uso:

python upload.py /Fotos

Utilize sua criatividade para extender essa idéia e criar aplicativos que ensinem e facilite sua vida.